i have given some examples. i think it is
appropriate to explain the principle that explains
how kites fly.
that is, Bernoulli's equation ( a statement of energy conservation
along the streamline of a fluid ).
m*g*h + (1/2) * (d*v^2 )+ p*(Vol1) = m*g*H + (1/2)*(dV^2) + P*(Vol2)
m*g*h and m*g*H represent gravitational potential and are equal so they can be eliminated
so:
(1/2)*(d*v^2) + p*(Vol1) = (1/2) (d*V^2) + P*(Vol2)
(1/2)*(d*v^2)-(1/2)*(d*V^2) = P*(Vol2) - p*(Vol1)
(1/2)*d*(v^2-V^2) = Vol(P-p)
d = density of air
v = initial velocity of air
V = velocity of air after it contacts the kite surface
we are going to assume that the volume of the air remains the same so
Vol = Vol1 = Vol2
p = pressure of air before it reaches the kite surface
P = pressure of air at the kite surface
we are interested in (P-p)
if the surface brings the velocity of air to a completely
perpendicular to the wind surface:
V = 0 -- that is capital V
and
(1/2) (d*v^2)= Vol*(P-p)
or, the difference in pressure DP = (P-p) is proportional to (1/2)(d*v^2)
though there is no complete analytical solution for all
shapes and orientations of surfaces, i am going to
use this equation as a starting point in the
calculations to come.
Monday, July 9, 2007
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2 comments:
This seems complicated!
wow!!! I wish I could do that. :)
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